2x^2+4x^2=60

Solution for 2x^2+4x^2=60 equation:

2x^2+4x^2=60

We move all terms to the left:

2x^2+4x^2-(60)=0

We add all the numbers together, and all the variables

6x^2-60=0

a = 6; b = 0; c = -60;
Δ = b2-4ac
Δ = 02-4·6·(-60)
Δ = 1440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1440}=\sqrt{144*10}=\sqrt{144}*\sqrt{10}=12\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{10}}{2*6}=\frac{0-12\sqrt{10}}{12}
=-\frac{12\sqrt{10}}{12}
=-\sqrt{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{10}}{2*6}=\frac{0+12\sqrt{10}}{12}
=\frac{12\sqrt{10}}{12}
=\sqrt{10}
$